WebThen, ∠BAE+∠AEF=180° Angles on the same side of a transversal line are supplementary Again, E F ∥ C D and CE is the transversal. Then, ∠DCE+∠CEF=180° (Angles on the same side of a transversal line are supplementary) ⇒∠DCE+∠AEC+∠AEF=180° ⇒∠DCE+∠AEC+180°-∠BAE=180° ⇒∠BAE-∠DCE=∠AEC Web2. In the given figure, O is the centre of a circle. If ∠OAB = 40° and C is a point on the circle, then ∠ACB = (a) 40° (b) 50°Ans (c) 80° (d) 100° 3. AB and CD are two equal chords of a circle with centre O such that ∠AOB = 80°, then ∠COD =
In Fig. 8.139, if AB CD, then x - Brainly
WebAB and CD are parallel lines cut by a transversal, thus the pair of alternate interior angles formed are equal. ∠AGE = ∠GED Thus, ∠AGE = x = 126° Line AB is intersected by line GE where x and z forms a linear pair. x + z = 180° 126° + z = 180° z = 180° - 126° = 54° Thus, ∠FGE = z = 54° ☛ Check: NCERT Solutions Class 9 Maths Chapter 6 WebOct 3, 2016 · From the given figure, it is given that the two chords of the circle with center O are equal that is AB=CD. Then, If the two chords of the circle are congruent, then their intercepted arcs are equal, therefore if … hepa filter to remove no2
In Fig. 6.30, if AB CD, EF ⊥ CD and ∠GED =126°, find ... - Cuemath
WebApr 9, 2024 · Solution For 3. In the given figure. if AB∥CD.CD∥EF and 3. 10y :3=3:7. find x. 4. In the given figure, if AB∥CD,∠APQ=50∘ and ∠PRD=127∘. find x and y. WebThe given figure is as follows: It is given that AB CD. Let us draw a line PQ parallel to AB and CD. It is given that, ∠1 +∠2 = 148° (i) Since, AB PQ Thus,∠APQangle and ∠1 are … WebMar 28, 2024 · Ex 6.2, 5 - In figure, if AB CD, ∠APQ = 50° & ∠PRD = 127° Chapter 6 Class 9 Lines and Angles Serial order wise Ex 6.2 Ex 6.2, 5 - Chapter 6 Class 9 Lines and Angles (Term 1) Last updated at March 28, 2024 by Teachoo Get live Maths 1-on-1 Classs - Class 6 to 12 Book 30 minute class for ₹ 499 ₹ 299 Transcript hepa filter used in pharmaceutical industry