WebNov 18, 2016 · This will return a slice of your dataframe which you can index using iloc. Here are your examples: Get first row where A > 3 (returns row 2) >>> df[df.A > 3].iloc[0] A 4 B 6 C 3 Name: 2, dtype: int64 If what you actually want is the row number, rather than using iloc, it would be df[df.A > 3].index[0]. Get first row where A > 4 AND B > 3: WebMay 21, 2024 · This outputs indices of all the rows whose values in the Sales column are greater than or equal to 300.. pandas.DataFrame.query() to Get Indices of All Rows Whose Particular Column Satisfies Given Condition pandas.DataFrame.query() returns DataFrame resulting from the provided query expression. Now, we can use the index …
Get row indices based on condition in Spark - Stack Overflow
Web37. I am looking for a condition which will return the index of a vector satisfying a condition. For example- I have a vector b = c (0.1, 0.2, 0.7, 0.9) I want to know the first index of b for which say b >0.65. In this case the answer should be 3. I tried which.min (subset (b, b > 0.65)) But this gives me 1 instead of 3. WebA better testcase is s = pd.Series ( [True, False, True, True, False, False, False, True], index=list ('ABCDEFGH')). Expected output: Index ( ['A', 'C', 'D', 'H'], ...). Since some solutions (esp. all the np functions) drop the index and use the autonumber index. – smci Apr 21, 2024 at 22:42 high bank balance screenshot
How can I get a value from a cell of a dataframe?
WebJul 15, 2024 · Method 1: Using for loop. In Python, we can easily get the index or rows of a pandas DataFrame object using a for loop. In this method, we will create a pandas … WebOct 4, 2024 · 3,680 4 36 61. the second solution didn't work on my dataframe, but the first solution did. The second solution works for accessing a value in a column. If you want the index of the value of a column, you would do countries ['Country_Name'].index [2] – Kaleb Coberly. Oct 11, 2024 at 2:49. Add a comment. WebApr 11, 2024 · 1 Answer. Sorted by: 1. There is probably more efficient method using slicing (assuming the filename have a fixed properties). But you can use os.path.basename. It will automatically retrieve the valid filename from the path. data ['filename_clean'] = data ['filename'].apply (os.path.basename) Share. Improve this answer. high bank cannabis dispensary